os.startfile() doesn't work

Asked by Bharatendu SOUMIL on 2019-05-22

Sometimes App.open () doesn't work. As a workaround i like using the python command:
os.startfile('Link to .exe')....but for some reason it throws the following error:

[error] Error caused by: Traceback (most recent call last): File "D:\Academic_Software\SikuliX\adminRights.sikuli\adminRights.py", line 20, in <module> os.startfile("C:\\Program Files\\4tiitoo\\NUIA\\Runtime\\bin\\NUIATrayMenu.exe") AttributeError: 'module' object has no attribute 'startfile' .

 ( I also did import os in the first line)

Any leads on this would be really appreciated

Kind regards,
Soumil

Question information

Language:
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Status:
Answered
For:
Sikuli Edit question
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Last query:
2019-05-24
Last reply:
2019-05-27
RaiMan (raimund-hocke) said : #1

os.startfile is not available in Python language level 2.7 (only in 3+)

SikuliX uses Jython with Python language level 2.7

Cool. thanks for the prompt respone. Also, is there a reason for App.open not working for certain apps, because for the above mentioned app it opens if i write a normal .py file and run it with the startfile() command

RaiMan (raimund-hocke) said : #3

How exactly are you using App.open() for the above mentioned .exe?
What version of SikuliX?

App.open("C:\\Program Files\\4tiitoo\\NUIA\\Runtime\\bin\\NUIATrayMenu.exe")
SikuliX 1.1.4
It doesnt report any error in the console log but doesn't do anything either

Worked fine for other apps like Chrome, Firefox

TestMechanic (ndinev) said : #6

try to type this into your console

C:\\Program Files\\4tiitoo\\NUIA\\Runtime\\bin\\NUIATrayMenu.exe

and see if program starts and releases the console

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