HowTo: Find one image out of a list of given images

My Sikuli on Python :)

use SikuliX 1.1.1 and use:

imgs = (img, img1, img2, ...) # see comment
found = os.path.split(findBest(imgs).getImageFilename())[1]
popup("%s is #%d" % (found, imgs.index(found)))

comment: (img, img1, img2, ...) is a list (tuple) of image filenames.
This might be programmatically constructed as a list [...] of image file names

the feature Region.findBest() is not yet documented. the listed images are searched in parallel at the same time and the match with the highest score is returned. To identify the index of the found image in the list you have to find the match's image filename in the list of images.

Thanks RaiMan, that solved my question.

in the cycle for me, it works this way:

while True:
    try:
        found = os.path.split(findBest(imgs).getImageFilename())[1]
        popup("%s is #%d" % (found, imgs.index(found)))
        break
    except:
        continue

tell me how to change the code in the case of the dictionary:

imgs = {'1':"1481019400547.png",'2': "1481019416947.png"}

if you want to do some more complex things, you have to learn some Python scripting !

dimgs = {'1':"1481019400547.png",'2': "1481019416947.png"}
imgs = dimgs.values()

... but your construct does not have any advantage over the simple list:
imgs = ["1481019400547.png","1481019416947.png"]

it is even more difficult to find out, which one matched - just try it ;-)
imgs.index(found)
will not help any longer.