How can I input a number and accept it as an integer in sikuli?

this has nothing to do with Sikuli but...

input doesn't have the ability to check the input type. You will have to process it yourself. Below is a trivial example:

while True:
    if type(input("Input a number")) is int:
        print "That's an integer"
        break
    else:
        print "That's not an integer. Enter integer!"

I need a number inputted by the user to automate in my calculator
Do you have any idea how to do it?
I want to make an automation where sikuli will ask the user to give two(2) integers/number and sikuli will do the rest to make it automated in inputing in calculator.
please help :'(

I need a number inputted by the user to automate in my calculator
Do you have any idea how to do it?
I want to make an automation where sikuli will ask the user to give two(2) integers/number and sikuli will do the rest to make it automated in inputing in calculator.
please help :'(

what's wrong with the solution I offered?

If you want to convert a string to an integer , use the function (for example, isdecimal()).
--------------------
errmsg = ""
while True:
    msg = "Input a number\n" + errmsg
    ans = input(msg)
    if ans == None:
        cancel = True
        break
    if ans.isdecimal():
        x = int(ans)
        cancel = False
        break
    else:
        errmsg = "'" + ans +"'" + " is not a number"

sorry:
If you want to evaluate the input value, use the function (for example, isdecimal()).
If you want to convert a string to an integer, use the function (for example, int()).

x= input("Input 1st Number:")
y= input("Input 2nd Number:")
op= input("choose operation to be used: + - * /")

if x == "1":
    click("1442372005556.png")
if x == "2":
    click("1442372023449.png")
if x == "3":
    click("1442372434642.png")
if x == "4":
    click("1442372451565.png")
if x == "5":
    click("1442372460538.png")
if x == "6":
    click("1442372475324.png")
if x == "7":
    click("1442372486937.png")
if x == "8":
    click("1442372506844.png")
if x == "9":
    click("1442372515627.png")
if x == "0":
    click("1442372522700.png")

/*opeationr to be used + - * / */
if op == "+":
    click("1442457788556.png")
if op == "-":
    click("1442457811305.png")
if op == "*":
    click("1442457824868.png")
if op == "/":
    click("1442457838430.png")

if y == "1":
    click("1442372005556.png")
if y == "2":
    click("1442372023449.png")
if y == "3":
    click("1442372434642.png")
if y == "4":
    click("1442372451565.png")
if y == "5":
    click("1442372460538.png")
if y == "6":
    click("1442372475324.png")
if y == "7":
    click("1442372486937.png")
if y == "8":
    click("1442372506844.png")
if y == "9":
    click("1442372515627.png")
if y == "0":
    click("1442372522700.png")

click("1442457857653.png") /*equal sign image

----so this is my codes looks like. And my problem here now is... I can't manipulate a number that composed of more than 1 digit :( Im so sorry, this is my first time using sikuli. I can't even find answers in google. :'( Im so desperate right now. tho I really want to learn this thing. thank you

ok, the principal approach is ok.

the return value of input() is a string. Python has a feature, to convert a string into a number:
num = int(str)

If the entered string represents a valid number, the x will contain this number, if not, the script will crash with an exception (which in turn can be handled).

For your case this would be the solution base:

xs = "" # the number as String
while xs == "":
    try:
        xs =input("Input 1st Number:")
        xn = int(xs) # check wether xs contains a valid number
    except:
        xs = "" # reset xs in case of not valid and repeat

now you need a sequence, to enter the number having n digits:

for digit in xs: # step through the digits in the string left to right
    if digit == "1":
        click("digit1.png")
   elif digit == "2":
        click("digit2.png")
    ...
    else:
        click("digit0.png")

... using if ... elif ... else is more efficient in this case, where only one case is valid among the possible 10 cases, since max 9 cases will be evaluated and the evaluation will end with the first success.

Since you need this sequence for 2 numbers, you could put it in a function:

def enterNumber(number):
    for digit in number: # step through the digits in the given string left to right
        if digit == "1":
            click("digit1.png")
        elif digit == "2":
            click("digit2.png")
        ...
        else:
            click("digit0.png")

... and the number input we add to a def also:

def enterNumber(text):
    number = "" # the number as String
    while number == "":
        try:
            number =input(text)
            int(number) # check wether number contains a valid number
        except:
            number = "" # reset number in case of not valid and repeat

    for digit in number: # step through the digits in number left to right
        if digit == "1":
            click("digit1.png")
        elif digit == "2":
            click("digit2.png")
        ...
        else:
            click("digit0.png")

now your script will look like this:

def enterNumber(text):
    number = "" # the number as String
    while number == "":
        try:
            number =input(text)
            int(number) # check wether number contains a valid number
        except:
            number = "" # reset number in case of not valid and repeat

    for digit in number: # step through the digits in number left to right
        if digit == "1":
            click("digit1.png")
        elif digit == "2":
            click("digit2.png")
        ...
        else:
            click("digit0.png")

enterNumber("Input 1st Number:")

ops = "+-*/"
while not op in ops:
    op= input("choose operation to be used: + - * /")

# operation to be used + - * /
if op == "+":
    click("plus.png")
elif op == "-":
    click("minus.png")
elif op == "*":
    click("mul.png")
else:
    click("div.png")

enterNumber("Input 2nd Number:")

click("equal.png")

If you decide to do more complex stuff with SikuliX, you should learn some Python basics:
http://sikulix-2014.readthedocs.org/en/latest/index.html

ok, I just realized that masuo already mentioned the int() function and I have to admit, that I was not aware of isdecimal().
But since this only works on unicode strings, I still would use int() in this case.