grabbing location details of matches out of a list

From another answer:

If you want to grab many matches of the same image at once, you have to use findAll().

matches = findAll(Pattern("image.png").similar(0.9))
for match in matches:
    click(match)

The returned matches are in arbitrary order. If you want them sorted somehow:

matches = findAll(Pattern("image.png").similar(0.9))
sorted_matches = sorted(matches, key=lambda m:m.y)
for match in sorted_matches:
    click(match)

This will go through the matches according to their y coordinate. Still the matches having the same y value, are in arbitrary order.

in the for loop you can do what you want: e.g build your list

points = ()
for match in sorted_matches:
    points.append((match.x, match.y))

or an iterator shortcut:

points = [ (m.x, m.y) for m in sorted_matches]

or just this:
matches = findAll(Pattern("image.png").similar(0.9))
points = [ (m.x, m.y) for m in sorted(matches, key=lambda m:m.y)]

now in points you have the 2-element-lists (x,y) of the top left corners of your matches from findAll in the order of increasing y value.

that works well, I now have the list showing:
points = [(735, 298), (735, 390), (827, 390), (966, 390), (643, 390), (781, 483), (920, 483), (643, 483), (920, 575)]

so [(x0,y0), (x1,y1),(x2,y2)........]

I would however like to get them in a format of

[x0,y0,x1,y1,x2,y2] to be able to perform calculations on the x values and the y values.
Using the above method retrieving points[0] returns (735,298), rather than just a single value.

I want to trigger a response if for example match 1 is located on the x-axis between 730 and 740, and between 290 and 300 on the y-axis.

thank you for your help and I apologize for not being clearer before
JD

Thanks RaiMan, that solved my question.