How to recognized 2 identical controls on page?

either
--1. restrict the search region to the area, where you expect the button to be or
--2. use Pattern() to raise the needed similarity

--1.
usually one finds something fixed on the page, that should be found definitely in all cases and the define the search region relative to this match.
Match m = find(top_image);
Region r = m.below()
r.click(something_inside_r)

--2.
s.click( (new Pattern("E://Test Data//Resume.png")).similar(0.95), 0);
we ask to find only images with a similarity score of >= 0.95, which normally is sufficient to distinguish between similar buttons

Hi RaiMan,

I really appreciated your quick and accurate response. I tried Option - 2 and it is working fine. Just eclipse IDE told me to do little correction. (Sharing because if any one refer this then it will be helpful.)

s.click((new Pattern("E://Test Data//Resume.png")).similar((float) 0.95), 0);

Solution given by you is working perfectly fine for me !!

Thanks a lot !!!!!

- PRIYANK

Hi RaiMan,

I am so sorry, I tried couple of times and surprise to see the behavior.

Except, FIRST TIME, it is again identifying Resume file upload control as Sample file upload control . I tried with both options but could not resolve the problem.

Can you please help me out.

Regards,
Priyank

Thanks for the feedback.

Yes, that you have to to specify the similarity as a float is still a glitch in the Java API. I have it on my list.

BTW: 0.95F does the same and looks a bit nicer ;-)

Yes, I can help you out.

But I need screenshots and the images you use to search.

Zip everything together and upload it somewhere in the net (e.g. Dropbox/Public) and post the link here or send it to my mail at https://launchpad.net/~raimund-hocke (do not post my real mail address here pls.).

Hello All,

My sincere apologies for multiple post. My problem gets resolved. There is nothing different solution which RaiMan said here but I just need to change code based on my application.

In My application, As said, we have two similar file upload control in sequence hence it was creating the problem.

1. Resume file upload
2. Sample file upload

So What I did is, I find match and create region of sample control (Which I don’t want to work with) and use above() method.

http://doc.sikuli.org/region.html

Above URL has really helped me out.

So code would look like,

                        Match m = s.find("..//Test Data//Sample.png"); //Sample file upload control.
   Region r = m.above();
   r.click("..//Test Data//ResumeBar.png"); //Input of Resume file upload

   s.wait("..//Test Data//WaitPopup.png");
   s.click("..//Test Data//Textbox.png", 0);
   s.type(null, "E:\\Test Data\\Textbox.png", 0);
   s.click("..//Test Data//OpenButon.png", 0);

Thanks a lot !!!!!

- PRIYANK

well done ;-)
thanks for coming back with your solution.

A third possibility is to use
findAll("..//Test Data//ResumeBar.png")
and sort the returned results by x- or y-coordinate.
Then you can pick the pattern you like, e.g. if you know the image is found twice and the right match is more left than the other, just pick the match with lower x-coordinate.
I know this might be more code to write but I just mention if for completeness :P
I guess it would also perform better because only one search is actually needed.

Thanks for solution and sharing the information.