[Java] Opening a file that does not have an extension

Uuups, it is Java that you requested, sorry ;-)

Use the according features, to run the start command from within Java.

I keep getting this error when I try the code out in Sikuli:

[error] An error occurs at line 3
[error] Error message: SyntaxError: ("mismatched character '\\n' expecting '''",

Line 3 is: dir = r"C:\test\"

My bad. My typing is horrible. I'm sorted, thanks

Thanks RaiMan, that solved my question.

a raw string r"" cannot have a backslash as last character.

That's why I am using os.path.join(), which builds a correct path without the need for the additional \

so use:
dir = r"C:\test"

*** from other question: /// pls. stay here

I need to get access to methods from org.sikuli.script.OS; in Java.

import org.sikuli.script.OS;

//Field
private OS myOS;.

public void Test(){

tempString = "filename";
  dir = "\\\\server\\folder\\folder\\";
  path = os.path.join(dir, tempString);
}

I get an error when I try to use os.path.join

Shouldn't I get access to all the methods in the class after I use the import statement?

There seems to be no other way. I tried a work around, but it failed. It's either I succeed with opening the file or opening the application. Never both.

if you want to do this in Java, you have to use the Java methods to construct the correct path string.

The final string for the start command in Java should print out like this:

start notepad.exe "\\sever\folder\filename"

It would be wise, to first check from a command line wether it does what you want.

Then go back to Java, construct the command correctly and submit it from within Java.

Thanks RaiMan. This syntax switching gets me at times. It's all coming together now