[Java] save captured screen or image on hard disk

Hi Vishal,
I am using something like this - when i take a screen capture - incase my test fails.
YOU can modify it as per your needs.

In my sikuli script , i have

m=capture(1,1,1020,900)
sName = sWorkingDir + sFileName+".png" # you can give values to these variables
shutil.copy(m,sName) # you need to import shutil in the beginning of your script

So this will copy the image file in your directory with whatever name you pass to it..

Hope that helps.
Anshu

Hi Anshu

Thanks for the pointers. One query thoug - whats your m object?

Also i think shutil is python utility...i am using java to write tests

I think you are using the Sikuli Java API on a very low level (bufferedImage = in memory bitstream).

You should stay on the file level, if you do not have the need to do something valuable with the image content.

String bf = s2.capture();

now bf contains the filename of the captured image in the temp folder. You have to simply move it to your image folder.

That was exactly, what Anshu proposed, saying, you have to adapt it to your situation.

BTW: I am not sure about your intention: your approach captures the screen and not the specified region.

if you want to capture the region: (transcribing Anshu's suggestion)

Region reg = new Region( 50,100,1300,200);
String imgFile = Screen.capture(reg)

BufferedImage bf = s2.capture().getImage();
File file1 = new File(imagePath+"/destFile.png");
ImageIO.write(bf, "png", file1);

import java.io.File;

This solved my problem

Thanks for all the pointers

solved by questioner himself

I tried using the shutil.copy(src, dest) but it gave me following error, any comments??

File "C:\Program Files\Sikuli X\sikuli-script.jar\Lib\shutil.py", line 85, in copy
File "C:\Program Files\Sikuli X\sikuli-script.jar\Lib\shutil.py", line 52, in copyfile
IOError: (13, 'EACCES', Imagefilename)