QCD order and QCD corrections included

Asked by Sarah

good morning

I generated the process in 2HDM type I
 g g > l+ l- h1 /a [ noborn= QCD ] , where l=e and muon.

after displied the diagrams
I got file of diagrams (triangles and box diagrams)with QCD=2, QED=3 and WEIGHTED=12.
the process in theses diagrams
g g > quarks in loop > A (cp odd Higgs Boson) > z + h (sm Higgs like =h1), then z goes to leptons.

my questions are
is the QCD order =2?

also, how can I know the included QCD corrections in the decay A>Zh?

best regards

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Olivier Mattelaer (olivier-mattelaer) said :
#1

>is the QCD order =2?

yes if that is what is written in the diagrams.

>also, how can I know the included QCD corrections in the decay A>Zh?

Not sure to understand your question here. Which I guess means that your answer is none.
This is a LO computation (at loop-level but still leading order) so not QCD correction should be included.
If you do have QCD correction this means that the computation is not correctly defined (and that you are not allowed to use the noborn= symbol)

Cheers,

Olivier

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Sarah (sarahwarad) said (last edit ):
#2

thank you Olivier
do you know what is the correct syntax to include QCD corrections for the process?

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Olivier Mattelaer (olivier-mattelaer) said :
#3

Hi,

Since we are not able to do two loop computation, Leading Order computation (so loop-induced) is the bast that we can do here.

Cheers,

Olivier

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Sarah (sarahwarad) said :
#4

thank you Olivier for your help
have a nice day