The value of cross-section for NLO is very High as compared to LO cross-section

Asked by mak

I am trying to calculate cross-section for (NLO) the process p p > z b [QCD]
but the value of cross-section i got is very high ( 872.5 ± 27 pb)
With LO calculation of same process i got correct value (p p > z b , z > mu+ mu-) which is 10.9 +-0.003 +-0.23 pb
relative paper is this https://arxiv.org/pdf/2003.11960.pdf
Cards information is
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Revision history for this message
Olivier Mattelaer (olivier-mattelaer) said :
#1

If you have a "B" in the final state, you have to use a four flavor model and not a five flavor model.

The cross-section for your process at LO in a 4 flavor model is zero since they are no diagram existing for such proccess.
Wrong setup for the flavor is typically not that critical at LO however this can creates huge issue at NLO since it can prevent some cancelation and therefore you get unphysical result.

Cheers,

Olivier

Revision history for this message
mak (mak5667) said :
#2

what if i use 5 flavor model for both LO and NLO

Revision history for this message
Olivier Mattelaer (olivier-mattelaer) said :
#3

You can not have a meaningful computation at NLO accuracy within the 5 flavour scheme for this process definition.

Revision history for this message
mak (mak5667) said :
#4

Is it possible to generate p p > z b b~ for both LO and NLO calculation?

Revision history for this message
Olivier Mattelaer (olivier-mattelaer) said :
#5

Yes you will even find that process in our paper: 1405.0301

Cheers,

Olivier

Revision history for this message
mak (mak5667) said :
#6

still the result for p p > z b b- [QCD] is very than cross-section of p p > z b b~

Revision history for this message
Olivier Mattelaer (olivier-mattelaer) said :
#7

So did you reproduce the number from 1405.0301?

Revision history for this message
mak (mak5667) said :
#8

https://arxiv.org/pdf/1405.0301.pdf Do you talking about this paper?

Revision history for this message
Olivier Mattelaer (olivier-mattelaer) said :
#9

yes process e.2 is your process.

Revision history for this message
mak (mak5667) said :
#10

 Cross-section : 79.64 +- 0.3068 pb
     Nb of events : 10000
this is my results for LO calculation

Revision history for this message
mak (mak5667) said :
#11

i used default cards

Revision history for this message
Olivier Mattelaer (olivier-mattelaer) said :
#12

Which is close enough of the papers if you did not match every setup of the paper.
(also we do have two code that can do LO computation, and do not know which one of the two you refer to)

Revision history for this message
mak (mak5667) said :
#13

where i can find those two codes?

Revision history for this message
mak (mak5667) said :
#14

in paper the value is 6.993±0.003·102

Revision history for this message
Olivier Mattelaer (olivier-mattelaer) said :
#15

one is

generate p p > Z b b~
output
launch

the other is

generate p p > Z b b~ [QCD]
output
launch
order=LO

The second method is usefull to compute K-factor since all the cards are the same as for the (default) case where order=NLO.
However that code is less optimal and is more limited (less cuts) than the first one. Both code have different default for the dynamical scale choice, default cut,...

Revision history for this message
mak (mak5667) said :
#16

and for NLO?

Revision history for this message
Olivier Mattelaer (olivier-mattelaer) said :
#17

There we do have only one code corresponding to
generate p p > Z b b~ [QCD]
output
launch
order=NLO

Revision history for this message
mak (mak5667) said :
#18

is it possible to decay Z in p p > Z b b~[QCD]

Revision history for this message
Olivier Mattelaer (olivier-mattelaer) said :
#19

You can ask Madspin to decay the Z (please refer to the madspin paper for details)

Can you help with this problem?

Provide an answer of your own, or ask mak for more information if necessary.

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