about decay length information

Asked by rojalin padhan on 2020-08-22

Hii,

I want to know about the decay length information which is written in the lhe file. According to the FAQ, https://answers.launchpad.net/mg5amcnlo/+question/403936 , this decay length is in the rest frame decaying particle, with out including the boost factor. Then it should be just one value, which is the inverse of total decay width. But I found different value for different events. If I plot those values I am getting an exponentially decaying distribution.

Could you please help me to know about why I am getting different values decay length for different event?

thanks,
rojalin

Question information

Language:
English Edit question
Status:
Solved
For:
MadGraph5_aMC@NLO Edit question
Assignee:
No assignee Edit question
Solved by:
Olivier Mattelaer
Solved:
2020-08-22
Last query:
2020-08-22
Last reply:
2020-08-22

No the point of this entry is to have the time after which that particle decay (and therefore this should indeed looks like an exponential).

Cheers,

Olivier

> On 22 Aug 2020, at 08:55, rojalin padhan <email address hidden> wrote:
>
> New question #692535 on MadGraph5_aMC@NLO:
> https://answers.launchpad.net/mg5amcnlo/+question/692535
>
> Hii,
>
> I want to know about the decay length information which is written in the lhe file. According to the FAQ, https://answers.launchpad.net/mg5amcnlo/+question/403936 , this decay length is in the rest frame decaying particle, with out including the boost factor. Then it should be just one value, which is the inverse of total decay width. But I found different value for different events. If I plot those values I am getting an exponentially decaying distribution.
>
> Could you please help me to know about why I am getting different values decay length for different event?
>
>
>
> thanks,
> rojalin
>
> --
> You received this question notification because you are an answer
> contact for MadGraph5_aMC@NLO.

rojalin padhan (rossy.mg) said : #2

Thanks Olivier Mattelaer, that solved my question.