Semi-leptonic final state of 4top production

Asked by Tobias Theil

Hi,

I want to perform a collider study concerning 4top production at the FCC to constrain some BSM models.

In order to not having to deal with the large backgrounds I am planning to look into semi-leptonic final states, same-sign dileptons or even trileptons. So my question is if there is a way to use the Madgraph decay syntax to generate only semi-leptonic decays or do I have to generate the full decay of the top quarks and pick out the final states I want?

In other words, is it possible to have the process p p > t t t~ t~ and tell Madgraph to e.g. decay one of the tops leptonically and the other hadronically (while decaying both t~ hadronically)?

Many thanks in advance,
Tobias

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Olivier Mattelaer
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This question was reopened

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Olivier Mattelaer (olivier-mattelaer) said :
#1

Hi,

You can do this (since 2.7.0):

generate p p > 2t 2t~, t > b l vl~, t > b j j, t~ > b~ j j

Cheers,

Olivier

> On 7 Mar 2020, at 12:33, Tobias Theil <email address hidden> wrote:
>
> New question #689189 on MadGraph5_aMC@NLO:
> https://answers.launchpad.net/mg5amcnlo/+question/689189
>
> Hi,
>
> I want to perform a collider study concerning 4top production at the FCC to constrain some BSM models.
>
> In order to not having to deal with the large backgrounds I am planning to look into semi-leptonic final states, same-sign dileptons or even trileptons. So my question is if there is a way to use the Madgraph decay syntax to generate only semi-leptonic decays or do I have to generate the full decay of the top quarks and pick out the final states I want?
>
> In other words, is it possible to have the process p p > t t t~ t~ and tell Madgraph to e.g. decay one of the tops leptonically and the other hadronically (while decaying both t~ hadronically)?
>
> Many thanks in advance,
> Tobias
>
> --
> You received this question notification because you are an answer
> contact for MadGraph5_aMC@NLO.

Revision history for this message
Tobias Theil (tobiasth) said :
#2

Thanks Olivier Mattelaer, that solved my question.

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Tobias Theil (tobiasth) said :
#3

Hi,

I am reopening this question because I noticed that using the syntax you suggested does also generate fully hadronic decays as well as fully leptonic decays of the top quark, not just the mixed one.

Again, thanks in advance,

Tobias

Revision history for this message
Best Olivier Mattelaer (olivier-mattelaer) said :
#4

Funny,

I thought that the decision of ordered/unordered decay was done particle by particle and not globally.
Clearly I was wrong
generate p p > 2t 2t~, t > b l vl~, t > b j j, t~ > b~ j j, t~ > b~ j j
should do it then,

Olivier

Revision history for this message
Tobias Theil (tobiasth) said :
#5

Yes, this syntax indeed only generates the mixed decays!

Revision history for this message
Tobias Theil (tobiasth) said :
#6

Thanks Olivier Mattelaer, that solved my question.