Decay Chain Syntax

Asked by Jasmina

Hello,

I am working with the following process p p > z z j j , ( z > l+ l- ) /h . Using this syntax, both z can decay in the same final state. Is there a way to generate a process where the z particles decay in different final states, namely one z in a e+e- state and the other z in mu+mu- ? Also I noticed that whether I use " /h " or not, it makes no difference in the number of diagrams that are generated for the process. This was not what I expected. Is there a reason for this? Thank you in advance.

Greetings,
Jasmina

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MadGraph5_aMC@NLO Edit question
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Solved by:
Olivier Mattelaer
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Best Olivier Mattelaer (olivier-mattelaer) said :
#1

Dear Jasmine,

I guess that the syntax that you are looking for is "generate p p > z z j j / h, z > e+ e- , z > mu+ mu-

Cheers,

Olivier
> On 24 May 2017, at 14:43, Jasmina <email address hidden> wrote:
>
> New question #634235 on MadGraph5_aMC@NLO:
> https://answers.launchpad.net/mg5amcnlo/+question/634235
>
> Hello,
>
> I am working with the following process p p > z z j j , ( z > l+ l- ) /h . Using this syntax, both z can decay in the same final state. Is there a way to generate a process where the z particles decay in different final states, namely one z in a e+e- state and the other z in mu+mu- ? Also I noticed that whether I use " /h " or not, it makes no difference in the number of diagrams that are generated for the process. This was not what I expected. Is there a reason for this? Thank you in advance.
>
> Greetings,
> Jasmina
>
> --
> You received this question notification because you are an answer
> contact for MadGraph5_aMC@NLO.

Revision history for this message
Jasmina (jasmin9) said :
#2

Thanks Olivier Mattelaer, that solved my question.