Matching and jet cuts
Hi,
I have problems in some understanding about matching procedure in MG + pythia. I have read
https:/
and
https:/
but I am a bit confused, so I try to ask
My goal is to compare the 0 j cs with the 0+1 j (matched) cs for a given process in order to understand how the addition of radiation can affect my process.
I'm doing the following two cases in the MSSM
i) 0 j:
generate p p > n1 x1-, x1-> n1 e- ve~ @1
with the standard run_card
and
ii) 0+1 j:
generate p p > n1 x1-, x1-> n1 e- ve~ @1
add process p p > n1 x1-, x1-> n1 e- ve~ @2
where in the run_card I have only modified
1 = ickkw ! 0 no matching, 1 MLM, 2 CKKW matching
30 = xqcut ! minimum kt jet measure between partons
and in the pythia card
SHOWERKT=T
QCUT=30
My question is the following.
I am not understanding if the cut on the ptj (default values is 20) is applied in the case of the 0+1 jet case.
What I want to do is to compare the two process without appling any cut on the jets in the second case in first instance, so I want to see how radiation affect that process, but I don't need a minimum value for those jets for my analysis in the first step
What I see from the parton plots is that the ptjet value has te minimum set by the xqcut value, so 30 and not 20.
( Is this related to the flag T = auto_ptj_mjj ! Automatic setting of ptj and mjj ? )
But from pythia plots looks like that no cuts on the jet are applied at the end, because the distributions starts from the value of 0.
So I am wondering if I am comparing i) with a matched cross section where cuts on ptj are applied or not.
I also have a question about the variable drjj that as far I understood should be set to zero in case of matching, so I am wondering which of the cuts of the run_card are applied to the events after matching with pythia and which not.
Sorry for the confusion and thanks for the help.
Daniele
Question information
- Language:
- English Edit question
- Status:
- Solved
- Assignee:
- de Visscher Edit question
- Solved by:
- de Visscher
- Solved:
- Last query:
- Last reply: