How to write a process

Asked by Muhammad Ahmad

Hi ,
I am trying to Produce events of Triple guage boson wzz or zzz.

i wrote in MadGraph
define w=w+ w-
generate p p > w z z, (w > j j , z > l+ l-)
Does this line will justify that both Z are decaying to Leptons ?
for Second case

generate p p > z z z, (z > l+ l-)
does it will justify that all the Z's are decaying to leptons only?????????????

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Olivier Mattelaer (olivier-mattelaer) said :
#1

Hi,

The parenthesis are required only in presence of subdecay:
Therefore this:
> define w=w+ w-
> generate p p > w z z, (w > j j , z > l+ l-)
is not valid since the z are not decay (it produces a warning that you try to decay a z where they are not:
WARNING: Decay without corresponding particle in core process found.
Decay information for particle(s) z is discarded.
Please check your process definition carefully.
This warning usually means that you forgot parentheses in presence of subdecay.
Example of correct syntax: p p > t t~, ( t > w+ b, w+ > l+ vl)
1 processes with 60 diagrams generated in 0.324 s

Indeed it tries to decay the Z from w > j j

the correct syntax is:
> define w=w+ w-
> generate p p > w z z, w > j j , z > l+ l-

Indeed both Z will be decayed

> generate p p > z z z, (z > l+ l-)

Here the parenthesis are not required but ok.
Indeed all Z will be decayed.

Cheers,

Olivier

On Oct 11, 2013, at 3:11 AM, Muhammad Ahmad <email address hidden> wrote:

> New question #237184 on MadGraph5:
> https://answers.launchpad.net/madgraph5/+question/237184
>
> Hi ,
> I am trying to Produce events of Triple guage boson wzz or zzz.
>
> i wrote in MadGraph
> define w=w+ w-
> generate p p > w z z, (w > j j , z > l+ l-)
> Does this line will justify that both Z are decaying to Leptons ?
> for Second case
>
> generate p p > z z z, (z > l+ l-)
> does it will justify that all the Z's are decaying to leptons only?????????????
>
> --
> You received this question notification because you are a member of
> MadTeam, which is an answer contact for MadGraph5.

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