Nodes selection feature request

Asked by emcamp on 2018-08-20


A very useful feature missing. Select all nodes between two selected nodes.

Select a node, then holding a keyboard button select another node, and inkscape would select all the nodes between the two selected nodes.

I hope you will find this feature important and it will not be difficult to implement.

Thank you.

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emcamp (inline) said : #1

between two nodes of one path*

Hachmann (marenhachmann) said : #2

Interesting idea. If you would like to make a feature request for this, please visit our bug tracker and search if someone else has already requested this - if you can't find any previous mention, feel free to open a new report for this.

emcamp (inline) said : #3

Hachmann, Hello.

I have openned the report here
can you accept it into the project, so that it is implemented?

Thank you.

Hachmann (marenhachmann) said : #4

Hi - no, sorry, I don't have the necessary permissions.

If you would like to speed up implementation, you could flesh out your suggestion, so devs need to think less:

- suggest a keyboard shortcut, making sure it's not already taken
- suggest how it would work in corner cases (e.g. if nodes are on different subpaths)
- suggest how it would work for closed paths (how is the correct part selected - it could be connecting the nodes clockwise, or counter-clockwise)

emcamp (inline) said : #5

This is the beauty of the method, that it is so simple, yet so powerful, i really miss it. There is no much to think about, simply take the shortest path every time. But i was really sad to see all the bugs has to be fixed with this really great app. I am afraid they will not want to look at feature requests yet

Hachmann (marenhachmann) said : #6

If it looks easy, and devs don't have to think about the design, because someone else already thought about the details, it can go surprisingly fast (this is no promise, just an experience). The clearer the task, the faster one can implement it. It doesn't sound very difficult to do, if the conditions are defined. Try it!

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