DOLFIN

marking curved boundary in dolfin by SubDomain

Asked by tedlai on 2010-03-02

I am trying to mark a curved boundary which is a PHYSICAL boundary, but it seems
dolfin does not take the boundary into account.

my curved boundary is just a semi-circle with a radius 0.5 and the center locates at (0, 0)

What I do is below,

class Cboundary(SubDomain):
     def inside(self,x,on_boundary):
         return on_boundary and (abs(x[0]*x[0]+x[1]*x[1]-0.25)<tol)

bc = DirichletBC(W.sub(0), noslip, Cboundary(), 'pointwise')

Changing the value of tol is not useful as I tried.

Question information

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DOLFIN Edit question
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Solved by:
tedlai
Solved:
2010-03-03
Last query:
2010-03-03
Last reply:
2010-03-02
Anders Logg (logg) said : #1

On Tue, Mar 02, 2010 at 08:09:35PM -0000, tedlai wrote:
> New question #102995 on DOLFIN:
> https://answers.launchpad.net/dolfin/+question/102995
>
> I am trying to mark a curved boundary which is a PHYSICAL boundary, but it seems
> dolfin does not take the boundary into account.
>
> my curved boundary is just a semi-circle with a radius 0.5 and the center locates at (0, 0)
>
> What I do is below,
>
> class Cboundary(SubDomain):
> def inside(self,x,on_boundary):
> return on_boundary and (abs(x[0]*x[0]+x[1]*x[1]-0.25)<tol)
>
> bc = DirichletBC(W.sub(0), noslip, Cboundary(), 'pointwise')
>
> Changing the value of tol is not useful as I tried.

Try changing to

  return abs(x[0]*x[0] + x[1]*x[1] - 0.25) < tol

on_boundary will only be True on the actual boundary of the mesh and
as I understand it your "boundary" is inside the domain.

--
Anders

tedlai (lailai) said : #2

Thank you so much for your answer,

I worked it out with your fomulation, anyway, actually, this curved boundary is not insed the domain,

but is a classical boundary.