configglue

Is there a shortcut method to skip the usual config boilerplate?

Asked by Stuart Metcalfe

For example, from the getting started docs, I need to do this:

    scp = SchemaConfigParser(MySchema())
    scp.read(['config.ini'])

    # support command-line integration
    op, opts, args = schemaconfigglue(scp)

    # validate the config (after taking into account any command-line
    # provided options
    is_valid, reasons = scp.is_valid(report=True)
ead the configuration files
    if not is_valid:
        op.error(reasons[0])

It would be great if I could just do:

MySchema.get_config(['config.ini'], cli-override=True)

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Launchpad Janitor (janitor) said : 		#1

This question was expired because it remained in the 'Open' state without activity for the last 15 days.

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Ricardo Kirkner (ricardokirkner) said : 		#2

With the latest configglue, you can just do

glue = configglue(MySchema, ['config.ini'])

This will read the configuration files and validate the configuration by default.

Given your suggestion we might look into changing validation to be optional.

Thanks,
Ricardo

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Ricardo Kirkner (ricardokirkner) said : 		#3

With the latest configglue, you can just do

glue = configglue(MySchema, ['config.ini'])

This will read the configuration files and validate the configuration by default.

Given your suggestion we might look into changing validation to be optional.

Thanks,
Ricardo

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