Pseudorapidity cut

Asked by Ribella

Hi,

We want to calculate any process with eta>2.5 cut. For example, How can we calculate the process A e-> A e with eta>2.5 for electron in final state?

Murat

Question information

Language:
English Edit question
Status:
Solved
For:
CalcHEP Edit question
Assignee:
No assignee Edit question
Solved by:
Ribella
Solved:
Last query:
Last reply:
Revision history for this message
Alexander Belyaev (alexander.belyaev) said :
#1

Hello,

the short answer is to use:
N(e)>2.5
statement in the cuts session

Slightly longer answer -- there is the help button "F1" -- you can find there many more details
as well as in the manual.

Regards,

Alexander

Revision history for this message
Ribella (ribella) said :
#2

Hello,

Thank you for your response.

However, we want to calculate exactly the process with our cut as follows,

-2.5>N(e)>2.5 ( |N(e)|>2.5)

Revision history for this message
Alexander Belyaev (alexander.belyaev) said :
#3

Just use the min and max bound from the menu!

On 07/07/17 12:23, Murat wrote:
> Question #646808 on CalcHEP changed:
> https://answers.launchpad.net/calchep/+question/646808
>
> Status: Answered => Open
>
> Murat is still having a problem:
> Hello,
>
> Thank you for your response.
>
> However, we want to calculate exactly the process with our cut as
> follows,
>
> -2.5>N(e)>2.5 ( |N(e)|>2.5)
>

--
Prof. Alexander S Belyaev (<email address hidden>)
http://www.hep.phys.soton.ac.uk/~belyaev/

School of Physics & Astronomy, University of Southampton, Office: 5047
SO17 1BJ, TEL.: +44 (0)23 8059 8509; FAX.: +44 (0)23 8059 3910
.....................................................................
Particle Physics Department, Rutherford Appleton Laboratory, Didcot,
OX11 0QX, TEL.: +44 (0)1235 445562; FAX.: +44 (0)1235 446733
.....................................................................
CERN: Office: 40 1-B20 Mailbox: E27910; ccid: 532076
TEL: +41 22 76 71642
______________________________________________________________________

Revision history for this message
Ribella (ribella) said :
#4

Hello,

Thanks Dr. Belyaev.